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Sagot :
85-12 = 73 degrees needed
4.186 J/degree Celsius, so
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J
2.06 x 10^5 J are needed
4.186 J/degree Celsius, so
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J
2.06 x 10^5 J are needed
Answer:
206,265.15 Joules are needed to warm 675 grams of water from 12 degrees Celsius to 85 degrees Celsius.
Explanation:
Between heat and temperature there is a direct proportionality relationship, where the constant of proportionality depends on the substance that constitutes the body. So, the equation that allows you to calculate heat exchanges is:
Q = c * m * ΔT
Where Q is the heat exchanged for a body of mass m, constituted by a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- Q=?
- c=[tex]4.186 \frac{J}{g*degrees Celsius}[/tex]
- m=675 g
- ΔT=Tfinal-Tinitial=85 degrees Celsius - 12 degrees Celsius= 73 degrees Celsius.
Replacing:
[tex]Q=4.186 \frac{J}{g*degrees Celsius}*675 g*73 degrees Celsius[/tex]
Resolving you get:
Q=206,265.15 J
206,265.15 Joules are needed to warm 675 grams of water from 12 degrees Celsius to 85 degrees Celsius.
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