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The height of an equilateral triangle is 18 meters. Find the perimeter of the triangle

Sagot :

[tex]h=18=\dfrac{a\sqrt3}{2}\\\\18=\dfrac{a\sqrt3}{2}\\ 36=a\sqrt3\\ a=\dfrac{36}{\sqrt3}\\ a=\dfrac{36\sqrt3}{3}\\ a=12\sqrt3\\\\ p=3a\\ p=3\cdot12\sqrt3\\ p=36\sqrt3[/tex]
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