Answered

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compute the value of the discriminant and give the number of real solutions of the quadratic equation.
−2x^2+6x-3=0

Sagot :

naǫ
[tex]-2x^2+6x-3=0 \\ \\ a=-2 \\ b=6 \\ c=-3 \\ \Delta=b^2-4ac=6^2-4 \times (-2) \times (-3)=36-24=12[/tex]

The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.
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