15Twilight
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How do you solve 2 log x = log 64?

Sagot :

naǫ
[tex]x>0 \\ \\ 2 \log x= \log 64 \\ \log x^2=\log 64 \\ x^2=64 \\ x=-8 \ \lor \ x=8 \ and \ x>0 \\ \boxed{x=8}[/tex]

Used formulas:
[tex]n \log_a b=\log_a b^n \\ \log_a b, b>0[/tex]
[tex]2\log { x } =\log { 64 } \\ \\ \log { \left( { x }^{ 2 } \right) } =\log { \left( { 8 }^{ 2 } \right) } \\ \\ { x }^{ 2 }={ 8 }^{ 2 }\\ \\ x={ \left( { 8 }^{ 2 } \right) }^{ \frac { 1 }{ 2 } }\\ \\ x=8[/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.