15Twilight
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

How do you solve 2 log x = log 64?

Sagot :

naǫ
[tex]x>0 \\ \\ 2 \log x= \log 64 \\ \log x^2=\log 64 \\ x^2=64 \\ x=-8 \ \lor \ x=8 \ and \ x>0 \\ \boxed{x=8}[/tex]

Used formulas:
[tex]n \log_a b=\log_a b^n \\ \log_a b, b>0[/tex]
[tex]2\log { x } =\log { 64 } \\ \\ \log { \left( { x }^{ 2 } \right) } =\log { \left( { 8 }^{ 2 } \right) } \\ \\ { x }^{ 2 }={ 8 }^{ 2 }\\ \\ x={ \left( { 8 }^{ 2 } \right) }^{ \frac { 1 }{ 2 } }\\ \\ x=8[/tex]
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.