Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

how many liters of 70% alcohol solution and 20% alcohol solution must be mixed to obtain 20 liters of 60% alcohol solution?

Sagot :

Answer:

16 liters of 70% alcohol

4 liters of 20% alcohol

Step-by-step explanation:

Let x = volume of 70% alcohol and y = volume of 20% alcohol. Since we need total of 20 liters, the first equation is x + y = 20. Next, calculate the amount of alcohol in the 20 liters of 60% alcohol. 60% is equivalent to 0.6, so there is 20*0.6 = 12 liters of alcohol in the 20 liter solution. Therefore the second equation is 0.7x + 0.2y = 12.

x + y = 20

0.7x + 0.2y = 12

2x + 2y = 40

7x + 2y = 120

-5x = -80

x = 16

16 + y = 20

y = 4

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.