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Solve question in image (yr 8 math, 40 pt)

Solve Question In Image Yr 8 Math 40 Pt class=

Sagot :

Answer:

y = 3

Step-by-step explanation:

(5y - 3)/4 + 6 = 3y

5y - 3 + 24 = 12y

7y = 21

y = 3

Check.

(5*3 - 3)/4 + 6 = 3*3

(15 - 3)/4 + 6 = 9

12/4 + 6 = 9

3 + 6 = 9

9 = 9

Answer: y = 3

Step-by-step explanation:

Given equation

[tex]\frac{5y~-~3}{4} ~+~6~=~3y[/tex]

Multiply 4 on both sides (to eliminate fraction)

[tex]\frac{5y~-~3}{4} *4~+~6*4~=~3y*4[/tex]

[tex](5y~-~3)~+~24~=~12y[/tex]

Expand parenthesis and combine like terms

[tex]5y~-~3~+~24~=~12y[/tex]

[tex]5y~+~21~=~12y[/tex]

Subtract 5y on both sides

[tex]5y~+~21~-~5y~=~12y~-~5y[/tex]

[tex]21~=~7y[/tex]

Divide 7 on both sides

[tex]21~/~7~=~7y~/~7[/tex]

[tex]\Large\boxed{y=3}[/tex]

Hope this helps!! :)

Please let me know if you have any questions