Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

12.2 g of N₂ gas at 1132 torr and 91°C has a volume of

Sagot :

CrystalQueen

Answer:

8.73 L

Explanation:

First, you need to convert grams to moles using the molar mass.

Molar Mass (N₂): 2(14.009 g/mol)

Molar Mass (N₂): 28.018 g/mol

12.2 grams N₂               1 mole
----------------------  x  ------------------------  =  0.435 moles N₂
                                 28.018 grams

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (torr)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (62.36 torr*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation.

P = 1132 torr                                   R = 62.36 torr*L/mol*K

V = ? L                                            T = 91 °C + 273.15 = 364.15 K

n = 0.435 moles

PV = nRT

(1132 torr)V = (0.435 moles)(62.36 torr*L/mol*K)(364.15 K)

(1132 torr)V = 9888.015

V = 8.73 L

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.