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Sagot :
The probability of rolling a sum of six or two even numbers.
is P = 1/3
How to find the probability?
Here we are rolling two dice, and each dice has 6 possible outcomes, then the total number of outcomes is:
6*6 = 36
Now, the outcomes that given a sum of 6 are:
dice 1 dice 2.
1 5
5 1
2 4
4 2
3 3
We have 5 outcomes there.
The outcomes where both numbers are even are:
dice 1 dice 2.
2 2
2 4
4 2
4 4
4 6
6 2
6 4
6 6
We have 8 outcomes here (such that 2 are in the ones we counted before).
Then the total number of outcomes that either add to 6 or have both even numbers are:
5 + 8 - 2 = 12
Then 12 out of 36 outcomes either add to 6 or have both even numbers, this means that the probability is:
P = 12/36 = 1/3
If you want to learn more about probability:
https://brainly.com/question/25870256
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