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Sagot :
- 3y-5x=10
Isolate y
- 3y=5x+10
- y=5/3x+10/3
Compare to slope intercept form y=mx+b
Slope=m=5/3
Answer:
[tex]\dfrac{5}{3}[/tex]
Step-by-step explanation:
To find the gradient (slope) of the given linear relation, use arithmetic operations to isolate y:
Given relation:
[tex]3y-5x=10[/tex]
Add 5x to both sides:
[tex]\implies 3y-5x+5x=10+5x[/tex]
[tex]\implies 3y=5x+10[/tex]
Divide both sides by 3:
[tex]\implies \dfrac{3y}{3}=\dfrac{5}{3}x+\dfrac{10}{3}[/tex]
[tex]\implies y=\dfrac{5}{3}x+\dfrac{10}{3}[/tex]
Slope-intercept form of a linear equation
[tex]y = mx+b[/tex]
where:
- m is the slope (gradient)
- b is the y-intercept
Comparing the rewritten equation with the slope-intercept formula, the gradient (slope) of the given linear relation is ⁵/₃.
Learn more about linear equations here:
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