Answer:
83in²
Step-by-step explanation:
This can also be expressed as;
Area of polygon=Area of ∆ABF +Area of rectangle BCDF + Area 0f ∆DEF
For ∆ABF;
Area of ∆ABO=∆AOF
Area of ∆ABF=2×Area of ∆ABO
Area of ∆ABO=1/2×Length×height
=1×4×7/2=28/2=14in
But area of ∆ABF=2×Area of ∆ABO
Area=2×14in=28in.
Area of rectangle;
Area=length×breadth
Area=5in×8in=40in.
Area of ∆DEF=2×Area of ∆EFG
Area=1/2× base× height
Area=1×2.5×6/2
Area=15/2=7.5in.
But area of ∆EFG=2×7.5in
=15in.
Area of polygon=28in+40in+15in=83in
