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There is a set of 12 cards numbered 1 to 12. A card is chosen at random. Event A is choosing a number less
than 6. Event B is choosing a number divisible by 3. A diagram is given below.
(Can you help with #4 if you know it:)

There Is A Set Of 12 Cards Numbered 1 To 12 A Card Is Chosen At Random Event A Is Choosing A Number Less Than 6 Event B Is Choosing A Number Divisible By 3 A Di class=

Sagot :

The number of permutations of picking 4 pens from the box is 30.

There are six different unique colored pens in a box.

We have to select four pens from the different unique colored pens.

We have to find in how many different orders the four pens can be selected.

What is a permutation?

A permutation is the number of different arrangements of a set of items in a particular definite order.

The formula used for permutation of n items for r selection is:

    [tex]^nP_r = \frac{n!}{r!}[/tex]

Where n! = n(n-1)(n-2)(n-3)..........1 and r! = r(r-1)(r-2)(r-3)........1

We have,

Number of colored pens = 6

n = 6.

Number of pens to be selected = 4

r = 4

Applying the permutation formula.

We get,

= [tex]^6P_4[/tex]

= 6! / 4!

=(6x5x4x3x2x1 ) / ( 4x3x2x1)

= 6x5

=30

Thus the number of permutations of picking  4 pens from a total of 6 unique colored pens in the box is 30.

Learn more about permutation here:

https://brainly.com/question/14767366

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