gggirl1122
Answered

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Please help
Rewrite in index notation and then differentiate. Answer in the same form as the question.
[tex]y=-5x^2 \sqrt{x}[/tex]

I think that [tex]y=-5x^2(x)^\frac{1}{2}[/tex]
is the first part rewriteing in index notation if u could tell me if I am right then differentiate just show each step as I know how to differentiate I just for some reason can get this question right.

Sagot :

ZeeSq

Answer:

I hope I've finally done justice to it.

Step-by-step explanation:

[tex]y=-5x^2 \sqrt{x}[/tex]

[tex]y=-5x^2(x)^\frac{1}{2}[/tex]

[tex]y=-5( {x}^{2 + \frac{1}{2} }) = - 5 {x}^{ \frac{5}{2} } [/tex]

[tex] \frac{dy}{dx} = - 5( \frac{5}{2}) {x}^{ \frac{5}{2} - 1 } [/tex]

[tex]\frac{dy}{dx} = ( \frac{ - 25}{2}) {x}^{ \frac{3}{2} } [/tex]

[tex]\frac{dy}{dx} = ( \frac{ - 25}{2}) \sqrt[3]{ {x}^{2} } [/tex]

View image ZeeSq
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