The equation y=[tex]-1/2\sqrt{x^{3} }[/tex] does not give result to y=-2/[tex]x\sqrt{x}[/tex].
Given two equations y=[tex]-1/2\sqrt{x^{3} }[/tex] and y=-2/[tex]x\sqrt{x}[/tex].
We are required to find that how the first equation will result in second equation.
Equation is like a relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c. It may be a linear equation,cubic or quadratic equation or many more depending on the power if variable.
Taking the first equation.
y=[tex]-1/2\sqrt{x^{3} }[/tex]
Interchange the power of x.
y=-1/2[tex]\sqrt{x} ^{3}[/tex]
Now multiply [tex]\sqrt{x}[/tex] three times.
y=-1/2[tex]\sqrt{x} \sqrt{x} \sqrt{x}[/tex]
Now [tex]\sqrt{x} \sqrt{x}[/tex] will result in x.
y=-1/2x[tex]\sqrt{x}[/tex]
You can see our result is not matching the second equation.
Hence the equation y=[tex]-1/2\sqrt{x^{3} }[/tex] does not give result to y=-2/[tex]x\sqrt{x}[/tex].
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