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Two jets leave an air base at the same time and travel in opposite directions. One jet travels 80 mi/h faster than the other. If the two jets are 11392 miles apart after 8 hours, what is the rate of each jet

Two Jets Leave An Air Base At The Same Time And Travel In Opposite Directions One Jet Travels 80 Mih Faster Than The Other If The Two Jets Are 11392 Miles Apart class=

Sagot :

The rate of the slower jet is 672 miles per hour.

The rate of the slower jet is 752 miles per hour.

How to find the rate of the jets?

Two jets leave an air base at the same time and travel in opposite directions.

One jet travels 80 mi/h faster than the other.

let

x = rate of the slower jet

faster jet = 80 + x

Therefore,

rate = distance / time

The two jets are 11392 miles apart.

(80 + x)8 + 8x = 11392

640 + 8x + 8x = 11392

640 + 16x = 11392

16x = 11392 - 640

16x = 10752

divide both sides by 16

x = 10752 / 16

x = 672 miles per hour

rate of the faster jet = 80 + 672 = 752 miles per hour

learn  more on rate here: https://brainly.com/question/13975895

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