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Sagot :
She can prove the point D. if segment AD ≅ segment CD, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent
How to illustrate the information?
It should be noted that line CD is a perpendicular line to line ACB intersecting point C. To understand it easier, if ACB is a horizontal lines, D is a point directly on top of C.
In this case, any point directly on C which perpendicular to line ACB will always the same to the endpoint of the segments.
Here, when segment AD ≅ segment CD, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent
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