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Sagot :
The amount of heat energy (in KJ) needed to convert 3 moles of water vapor into hydrogen gas and oxygen gas is 1450.8 KJ
Balanced equation
We'll begin by writing the balanced equation. This is illustrated below:
2H₂ + O₂ --> 2H₂O ΔH = 483.6 KJ
From the balanced equation above,
2 moles of water (H₂O) required 483.6 KJ to produce hydrogen gas and oxygen gas
How to determine the heat energy needed to convert 3 moles of water to hydrogen gas and oxygen gas
The heat energy needed to convert 3 moles of water can be obtained as illustrated below:
From the balanced equation above,
2 moles of water (H₂O) required 483.6 KJ to produce hydrogen gas and oxygen gas
Therefore,
3 moles of water (H₂O) will require = 3 × 483.6 = 1450.8 KJ to produce hydrogen gas and oxygen gas
Thus, we can conclude that the energy needed to convert 3 moles of water is 1450.8 KJ
Learn more enthalpy change:
https://brainly.com/question/11967318
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