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f(t) = 0.25t2 − 0.5t + 3.5

Sagot :

abidemiokin

The resulting value of the function when the values of t is 2 and 6 are 3.5 and 6.5 respectively

Function and values

Functions are expressions in form of variables. Given the following quadratic equation expressed as:

f(t) = 0.25t^2 − 0.5t + 3.5

We can find the equivalent value of the function when the value of t a re 2 and 6.

If the value of t is 2. hence;

f(2) =  0.25(2)^2 − 0.5(2) + 3.5

f(2) = 1 - 1 + 3.5

f(2) = 3.5

If the value of t is 6, hence;

f(6) = 0.25(6)^2 − 0.5(6) + 3.5

f(6) = 9 - 3 + 3.5

f(6) = 6.5

Hence the resulting value of the function when the values of t is 2 and 6 are 3.5 and 6.5 respectively

Learn more on functions and values here: https://brainly.com/question/2284360

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