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Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group because he will be arriving late. How many ways can the instructor choose the first group of four education students?.

Sagot :

330 ways can the instructor choose the first group of four education students.

What is probability in math?

  • Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty.
  • We can predict only the chance of an event to occur i.e. how likely they are to happen, using it.

Given:

12 students

3 groups consisting of 4 students.

Mark can't be in the first group.

The combination formula that I used is =  n! / r!(n-r)!

where: n = number of choices ; r = number of people to be chosen.

This is the formula I used because the order is not important and repetition is not allowed.

Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.

numerator: n! = 11! = 39,916,800

denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960

Combination = 39,916,800 / 120,960 = 330

Therefore, There are 330 ways that the instructor can choose 4 students for the first group.

Learn more about probability

brainly.com/question/14281453

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