The coordinates for P and Q are as follows,
P = (a, a)
Q = (0, a)
Finding the Missing Coordinates:
Triangle OPQ is an isosceles triangle, hence two of its legs are equal.
Since the coordinates of the end point of the leg OQ lies on the y-axis, and OP is parallel to x-axis, OQ ⊥ QP ............ (1)
Also, it indicates that the x- coordinate of point Q is 0.
⇒ The coordinates of point Q are (0, a)
From (1), we can infer that,
OP = OQ [∵ OP is the hypotenuse]
⇒ The distance of point P from x-axis = a
The distance of point P from y-axis =a
Hence, the coordinates of point P are given as (a, a).
Learn more about coordinates here:
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