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Sagot :
Answer: [tex]50^{\circ}[/tex]
Step-by-step explanation:
[tex]m\angle CAB=m\angle CAD=80^{\circ}[/tex] (angle bisector)
[tex]m\angle ACB=20^{\circ}[/tex] (one-eighth of [tex]\angle BAD[/tex])
[tex]m\angle ABC=80^{\circ}[/tex] (sum of angles in a triangle)
[tex]\overline{AC} \cong \overline{BC}[/tex] (converse of base angles theorem)
[tex]m\angle ADC=50^{\circ}[/tex] (base angles theorem)

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