At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

In quadrilateral ABCD, the sides BC and AD are congruent. The diagonal AC is the bisector of the angle BAD=160 degrees, thats is 8 times greater than angle ACB. Find the measure of angle ADC

pls help

Sagot :

Answer: [tex]50^{\circ}[/tex]

Step-by-step explanation:

[tex]m\angle CAB=m\angle CAD=80^{\circ}[/tex] (angle bisector)

[tex]m\angle ACB=20^{\circ}[/tex] (one-eighth of [tex]\angle BAD[/tex])

[tex]m\angle ABC=80^{\circ}[/tex] (sum of angles in a triangle)

[tex]\overline{AC} \cong \overline{BC}[/tex] (converse of base angles theorem)

[tex]m\angle ADC=50^{\circ}[/tex] (base angles theorem)

View image Medunno13