Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
18mL of a 16M H₂SO₄ solution is required to prepare.
Dilution is the process of lowering a solute's concentration in a solution. It usually just involves mixing the solution with more solvent, and much more water. A solution is diluted when more solvent is added without increasing solute. The final mixture is thoroughly mixed to make sure that every component is the same.
The formula for the dilution of a solution is
M₁V₁ = M₂V₂
where,
M is molarity and V is the volume of the solution in liters.
Known,
M₁ = 16M = 16 mol/ L
M₂ = 0.15M = 0.15 mol / L
V₂ = 2.0 × [tex]10^3[/tex] ml
= 2L
∴ [tex]V_1 =\frac{M_2 V_2}{M_1}[/tex]
[tex]V_1 = \frac{0.15 * 2}{16}[/tex]
[tex]= \frac{0.3}{16}[/tex]
[tex]= 0.018 L[/tex]
[tex]V_1 = 0.018L[/tex] × [tex]1000 mL[/tex]
[tex]= 18 mL[/tex]
Therefore, 18mL of a 16M H₂SO₄ solution is required to prepare.
Learn more about dilution here:
https://brainly.com/question/11493179
#SPJ4
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.