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How many milliliters of an 16m (h2so4) solution is required to prepare 2. 0×10^3ml of 0. 15m solution?

Sagot :

18mL of a 16M H₂SO₄ solution is required to prepare.

Dilution is the process of lowering a solute's concentration in a solution. It usually just involves mixing the solution with more solvent, and much more water. A solution is diluted when more solvent is added without increasing solute. The final mixture is thoroughly mixed to make sure that every component is the same.

The formula for the dilution of a solution is

                                       M₁V₁ = M₂V₂

where,

M is molarity and V is the volume of the solution in liters.

Known,

M₁ = 16M = 16 mol/ L

M₂ = 0.15M = 0.15 mol / L

V₂ = 2.0 × [tex]10^3[/tex] ml

    = 2L

∴ [tex]V_1 =\frac{M_2 V_2}{M_1}[/tex]

  [tex]V_1 = \frac{0.15 * 2}{16}[/tex]

       [tex]= \frac{0.3}{16}[/tex]

       [tex]= 0.018 L[/tex]

  [tex]V_1 = 0.018L[/tex]  × [tex]1000 mL[/tex]

       [tex]= 18 mL[/tex]

Therefore, 18mL of a 16M H₂SO₄ solution is required to prepare.

Learn more about dilution here:

https://brainly.com/question/11493179

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