Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
18mL of a 16M H₂SO₄ solution is required to prepare.
Dilution is the process of lowering a solute's concentration in a solution. It usually just involves mixing the solution with more solvent, and much more water. A solution is diluted when more solvent is added without increasing solute. The final mixture is thoroughly mixed to make sure that every component is the same.
The formula for the dilution of a solution is
M₁V₁ = M₂V₂
where,
M is molarity and V is the volume of the solution in liters.
Known,
M₁ = 16M = 16 mol/ L
M₂ = 0.15M = 0.15 mol / L
V₂ = 2.0 × [tex]10^3[/tex] ml
= 2L
∴ [tex]V_1 =\frac{M_2 V_2}{M_1}[/tex]
[tex]V_1 = \frac{0.15 * 2}{16}[/tex]
[tex]= \frac{0.3}{16}[/tex]
[tex]= 0.018 L[/tex]
[tex]V_1 = 0.018L[/tex] × [tex]1000 mL[/tex]
[tex]= 18 mL[/tex]
Therefore, 18mL of a 16M H₂SO₄ solution is required to prepare.
Learn more about dilution here:
https://brainly.com/question/11493179
#SPJ4
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.