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Sagot :
The value of the base b in the isosceles triangle is 3.1 inches.
According to the statement
we have given that the
equation is 2a + b = 15.7 and if one longer sides is 6.3 centimeter.
And we have to find the length of the base. Then
2a + b = 15.7
Here a is 6.3 cm then
Substitute the values in it then
2a + b = 15.7
2(6.3) + b = 15.7
After solving the equation
12.6 + b = 15.7
b = 15.7 - 12.6
Now we get the value of base b which is 3.1.
So, b = 3.1
So, The value of the base b in the isosceles triangle is 3.1 inches.
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Question:
This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the triangle is 15.7 centimeters. The equation 2a + b = 15.7 can be used to find the side lengths.
If one of the longer sides is 6.3 centimeters, what is the length of the base?
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