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An isosceles triangle has two sides of equal length, a, and a base, b. The perimeter of the triangle is 15.7 inches, so
the equation to solve is 2a + b = 15.7.
ayer/
If we recall that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side,
which lengths make sense for possible values of b? Select two options.


Sagot :

The value of the base b in the isosceles triangle is 3.1 inches.

According to the statement

we have given that the

equation is 2a + b = 15.7 and if one longer sides is 6.3 centimeter.

And we have to find the length of the base. Then

2a + b = 15.7

Here a is 6.3 cm then

Substitute the values in it then

2a + b = 15.7

2(6.3) + b = 15.7

After solving the equation

12.6 + b = 15.7

b = 15.7 - 12.6

Now we get the value of base b which is 3.1.

So, b = 3.1

So, The value of the base b in the isosceles triangle is 3.1 inches.

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Question:

This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the triangle is 15.7 centimeters. The equation 2a + b = 15.7 can be used to find the side lengths.

If one of the longer sides is 6.3 centimeters, what is the length of the base?

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