Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The age of a father is three times that of his son. In ten year's time their ages will add up to 68 years. If the son is x years old today write down an algebraic expression for: the present age of the father and the son's age in ten year's time and the father's age in 10 year's time.​

Sagot :

bunnuika

Answer:

46 and 22

Step-by-step explanation:

let the father b (f) and d son is (s)

so

f=3s.....(1)

(f+10) +(s+10)=68 .... (2)

substitute f=3s in equation (2)

we have

(3s+10)+(s+10)=68

4s+20=68

4s=68-20

4s=48

s=12 .......(3)

substitute (3) in (1)

f=3*12

which f=36

in 10 year time

f+10 =46

s+10=22

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.