Answer:
[tex]x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}[/tex]
Step-by-step explanation:
So when it says simplify the right side, all it's doing is distributing the square root across division.
So when we distribute the square root we get the fraction
[tex]\frac{\sqrt{b^2-4ac}}{\sqrt{4a^2}}[/tex]
And it's important to know that you cannot distribute the square root across addition/subtraction, but you can with multiplication.
There's a radical identity that states: [tex]\sqrt[n]{a} * \sqrt[n]{b} = \sqrt[n]{ab}[/tex] and this works both ways, so we can use this to combine like radicals or separate them into multiple. In this case we can separate the square root of 4a^2 into two radicals
[tex]\frac{\sqrt{b^2-4ac}}{\sqrt{4} * \sqrt{a^2}}[/tex]
And from here it's pretty easy to see that the square root of 4 is 2, and the square root of a^2 is a, since the square exponent and square root just cancel out.
So we get the following expression on the right side
[tex]\frac{\sqrt{b^2-4ac}}{2a}[/tex]
