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Sagot :
Considering the given function, it is found that:
- When t = 0, d = 0 meters.
- When t = 0.5, d = 1.25 meters.
- When t = 1, d = 5 meters.
- When t = 1.5, d = 11.25 meters.
- When t = 2, d = 20 meters.
Since the changes for each 5 second interval are not the same, the ball is not traveling at a constant speed.
What is the function for the distance traveled by the ball?
The function is:
d = 5t².
Hence:
- When t = 0, d = 5 x 0² = 0 meters.
- When t = 0.5, d = 5 x 0.5² = 1.25 meters.
- When t = 1, d = 5 x 1 = 5 meters.
- When t = 1.5, d = 5 x 1.5² = 11.25 meters.
- When t = 2, d = 5 x 2² = 20 meters.
Since the changes for each 5 second interval are not the same, the ball is not traveling at a constant speed.
More can be learned about functions at https://brainly.com/question/25537936
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