The solutions to the quadratic equation -t² + 7t = 0 are 7 and 0.
Hence, x = 7, 0.
What are the solutions to the quadratic equation?
Quadratic equation is simply an algebraic expression of the second degree in x. Quadratic equation in its standard form is;
ax² + bx + c = 0
Where x is the unknown
To solve for x, we use the quadratic formula
x = (-b±√(b² - 4ac)) / (2a)
Given the equation;
-t² + 7t = 0
Comparing with the standard form.
We substitute into the quadratic formula.
x = (-b±√(b² - 4ac)) / (2a)
x = (-7±√( (7)² - ( 4 × -1 × 0) ) / (2 × -1)
x = (-7±√( 49 - 0) ) / (-2)
x = (-7±√49 ) / (-2)
x = (-7±7 ) / (-2)
x = (-7-7 ) / (-2), (-7+7 ) / (-2)
x = -14/(-2), 0/(-2)
x = 7, 0
The solutions to the quadratic equation -t² + 7t = 0 are 7 and 0.
Hence, x = 7, 0.
Learn more about quadratic equations here: brainly.com/question/1863222
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