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Sagot :
The value of ''n" in the hydrate formula is 10
Moles of anhydrous sodium tetraborate:
Mass of anhydrous NA2B4O7 = 2.64g
Molar mass of NA2B4O7 = 201.224 g/mol
Number of Moles of anhydrous NA2B4O7 = Mass of NA2B4O7 / Molar mass of NA2B4O7
= 2.64 / 201.224
= 0.0131 mol
Mass of water in 5.00g of NA2B4O7 = 5.00 - 2.64
= 2.36 g
Moles of water = 2.36 / 18.015
= 0.1307 mol
The whole number ratio = moles of water / moles of anhydrous sodium tetra borate
= 0.1307 / 0.0131
The whole number ratio = 10
Hence the value of n in the hydrate formula is 10.
NA2B4O7. 10H2O
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