Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A 5.00 g sample of hydrated sodium tetraborate, Na2B4O7 x nH2O is heated to drive off the water. After heating, 2.64 g of anhydrous Na2B4O7 reasons. What is the value of "n" in the hydrate formula

A 500 G Sample Of Hydrated Sodium Tetraborate Na2B4O7 X NH2O Is Heated To Drive Off The Water After Heating 264 G Of Anhydrous Na2B4O7 Reasons What Is The Value class=

Sagot :

The value of ''n" in the hydrate formula is 10

Moles of anhydrous sodium tetraborate:

Mass of anhydrous NA2B4O7 = 2.64g

Molar mass of NA2B4O7 = 201.224 g/mol

Number of Moles of anhydrous NA2B4O7 = Mass of NA2B4O7 / Molar mass of NA2B4O7

                                                     = 2.64 / 201.224

                                                     = 0.0131 mol

Mass of water in 5.00g of NA2B4O7 = 5.00 - 2.64

                                                              = 2.36 g

Moles of water = 2.36 / 18.015

                          = 0.1307 mol

The whole number ratio = moles of water / moles of anhydrous sodium tetra borate

                                           = 0.1307 / 0.0131

The whole number ratio = 10

Hence the value of n in the hydrate formula is 10.

NA2B4O7. 10H2O

Learn more about hydrated sodium tetraborate on

https://brainly.com/question/13959989

#SPJ1

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.