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Sumalee and Julio are selling cheesecakes for a school fundraiser. Customers can buy pecan
cheesecakes and apple cheesecakes. Sumalee sold 6 pecan cheesecakes and 12 apple
cheesecakes for a total of $270. Julio sold 12 pecan cheesecakes and 9 apple cheesecakes for a
total of $285. Find the cost each of one pecan cheesecake and one apple cheesecake.

Sagot :

The cost of the pecan cheesecake and one apple cheesecake are $11 and $17.

According to the statement

we have given that the Sumalee sold 6 pecan cheesecakes and 12 apple

cheesecakes for a total of $270. Julio sold 12 pecan cheesecakes and 9 apple cheesecakes for a

total of $285.

And we have to find that the cost each of one pecan cheesecake and one apple cheesecake.

So, for this purpose,

Let x be the cost of each pecan cheesecake.

and y be the cost of each one apple cheesecake.

Then The equation become

6x + 12y = 270  -(1)

12x + 9y = 285  -(2)

From elimination method

multiply (1) by 12 and (2) by 6 then

72x + 144y = 3240

72x + 54y = 1710

Now eliminate x from them then the equation become

90y = 1530

here y = 17

then the x become

6x + 12y = 270  

6x + 12(17) = 270  

6x = 270-204

6x = 66

and x become 11.

So, The cost of the pecan cheesecake and one apple cheesecake are $11 and $17.

Learn more about Elimination method here

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