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Sagot :
The value of the x from the given equation is a +i and -i and +5i and -5i.
According to the statement
we have given that the equation [tex]x^4 + 6x^2 +5 =0[/tex]
and we have to find the value of x by the u substitution.
So,
The given equation is
[tex]x^4 + 6x^2 +5 =0[/tex]
Put [tex]x^2 = u[/tex]
By substitution method
Then the equation become
[tex]u^2 +6u +5 = 0[/tex]
And solve the equation then
[tex]u^2+ u +5u +5 = 0[/tex]
Then
u(u +1) + 5(u +1) = 0
(u+5) (u +1) = 0
Then
the value of u is -1 and -5 then
The value of x is
[tex]x = \sqrt{u}[/tex]
x = √-5 And √-1
Then the value of x is +i and -i and +5i and -5i.
So, The value of the x from the given equation is a +i and -i and +5i and -5i.
Learn more about substitution method here
https://brainly.com/question/22340165
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