Answered

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A welding torch requires 602.1 L of ethylene gas at 2.77 atm. What will be the pressure of the gas if ethylene is supplied by a 110.6 L tank?

Sagot :

PV=PV
(602.1 L)(2.77atm) = (110.6 L) (X atm)
1667.817=110.6X
15.07971971 atm = X
Rounds to 15.1 (sig figs so much fun)
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