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Sagot :
The tensile reinforcement is required at midspan is 3.103 in^2 and the total depth h is required is 17 in.
organizing the information given in the statement:
- t beam is to be designed to carry a uniformly distributed load on a 20-ftsimple span
- The total moment to be carried is mu-5780
- shear and clearance requirements, are b 20 in, b 10 in, he-5in, and d 20 in. Iffy 60 ksi and fe-4ksi
With that infromation we can say, total moment to be caried out in the bean is:
M=5780 in kips
Characteristics strength of concreete is 4ksi
Characteristics strength of steel is 60ksi
Find the depht of stress block:
[tex]a=\frac{A_s*f_y}{0.85*fc}[/tex]
Substitute 4ksi in fc, 60 ksi in fy we have:
[tex]a= 17.65 A_s[/tex]
Find the area of tensile reinforcement:
[tex]\phi M= \phi A_sf_y(d-a/2)\\5780=A_s*60(20-17.65A_s/2)\\A_s=3.103 in^2[/tex]
Provide 3 stirrups of 9 inches bar (wich has a diameter of 1.128 inches)
Provide 3 inch as cover fot T-beam, therefore the effective depth is:
h=20-3=17 in
See more about tensile-reinforced at brainly.com/question/18273420
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