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If a /b=p/q, then (a + b)/b=
b/(a+d)


Sagot :

If a /b = p/q, then (a + b)/b = b/(a+d) exists FALSE.

What is Componendo Property of fractions?

Let a, b, c, d be the four numbers, then

if a : b = c : d then (a + b) : b :: (c + d) : d.

If a : b :: c : d then (a - b) : b :: (c - d) : d.

Given equation,

[tex]$\Rightarrow \frac{a}{b}=\frac{p}{q}$[/tex]

Adding 1 on both sides of the equation, we get

[tex]${data-answer}amp;\Rightarrow \frac{a}{b}+1=\frac{p}{q}+1 \\[/tex]

[tex]${data-answer}amp;\Rightarrow \frac{a+b}{b}=\frac{p+q}{q}[/tex]

This rule exists also comprehended as the Componendo property of fractions.

Therefore, [tex]$\frac{a+b}{b}=\frac{p+q}{q}$[/tex] then a = pb + q but the hypothesis says that

a = (p+b) / q.

If a /b = p/q, then (a + b)/b = b/(a+d) exists FALSE.

To learn more about the Componendo property of fractions refer to:

https://brainly.com/question/2933117

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