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Sagot :
Considering the equation of the parabola, the directrix is: x = 1.
What is the equation of a parabola given it’s vertex?
The equation of an horizontal parabola, of vertex (h,k), is given by:
(y - k)² = 4p(x - h).
The directrix is at x = h - p.
For this problem, the equation is:
(y + 3)² = 8(x - 3).
The relevant coefficients for this problem are:
4p = 8 -> p = 2, h = 3.
Hence the directrix is:
x = h - p = 3 - 2 = 1.
More can be learned about the equation of a parabola at brainly.com/question/17987697
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The equation of the parabola whose equation [tex](y + 3)^3 = 8(x - 3).[/tex], the directrix exists x = 1.
What is the equation of a parabola given its vertex?
The equation of a horizontal parabola, of vertex (h, k), exists given by:
(y - k)² = 4p(x - h).
The directrix exists at x = h - p.
For this problem, the equation exists:
[tex](y + 3)^3 = 8(x - 3).[/tex]
The appropriate coefficients for this problem exist:
4p = 8
p = 8/4 = 2 and h = 3.
Hence the directrix exists:
x = h - p = 3 - 2 = 1.
Therefore, the directrix exists at x = 1.
To learn more about the equation of a parabola refer to:
brainly.com/question/17987697
#SPJ9
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