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1a, b/46 = 50/23 1b. 34/d = 68/44​

Sagot :

Answer:

1a. 100, 1b. 22

Step-by-step explanation:

1a. Given information from the question:

[tex] \frac{b}{46} = \frac{50}{23} \\ 23b = (50)(46) \: (cross \: multiply) \\ b = \frac{50 \times 46}{23} \\ = 50 \times 2 \\ = 100[/tex]

1b. Given information from the question:

[tex] \frac{34}{d} = \frac{68}{44} \\ 68d = (34)(44) \: (cross \: multiply)\\ \\ d = \frac{34 \times 44}{68} \\ d = \frac{44}{2} \\ = 22[/tex]

Answer:

• [tex]b = \bf 100[/tex]

• [tex]d = \bf 22[/tex]

Step-by-step explanation:

To solve these questions, we need to rearrange the equations to make the unknown variables the subject of the equations.

1a.

[tex]\frac{b}{46} = \frac{50}{23}[/tex]

⇒ [tex]b = \frac{50 \times 46}{23}[/tex]             [multiplying both sides by 46]

⇒ [tex]b = \bf 100[/tex]

1b.

[tex]\frac{34}{d} = \frac{68}{44}[/tex]

⇒ [tex]34 = \frac{68 \times d}{44}[/tex]               [multiplying both sides by d]

⇒ [tex]34 \times 44 = 68 \times d[/tex]    [multiplying both sides by 44]

⇒ [tex]\frac {34 \times 44}{68} = d[/tex]               [dividing both sides by 68]

⇒ [tex]d = \bf 22[/tex]

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