The total number of integral solutions of x + y + z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and z ≥ 3 is; 59 integer solutions
How to find the number of Integral Solutions?
We are given the condition that;
−3 ≤ x ≤ 4
Thus, we will use x values of -3, -2, -1, 0, 1, 2, 3, 4
When;
x = -3 and y = 2, in x + y + z = 12, solving for z gives z = 13
x = -3 and y = 3, in x + y + z = 12, solving for z gives z = 12
x = -3 and y = 4, in x + y + z = 12, solving for z gives z =11
x = -3 and y = 5, in x + y + z = 12, solving for z gives z = 10
x = -3 and y = 6, in x + y + z = 12, solving for z gives z = 9
x = -3 and y = 7, in x + y + z = 12, solving for z gives z = 8
x = -3 and y = 8, in x + y + z = 12, solving for z gives z = 7
x = -3 and y = 9, in x + y + z = 12, solving for z gives z = 6
x = -3 and y = 10, in x + y + z = 12, solving for z gives z = 5
x = -3 and y = 11, in x + y + z = 12, solving for z gives z = 4
Thus, there are 10 solutions with x =-3
Repeating the above with x = -2, we will have 10 solutions
Similarly, with x = -1, we will have 9 more solutions
Similarly, with x = 0, we will have 8 more solutions.
Similarly, with x = 1, we will have 7 more solutions.
Similarly with x = 2, we will have 6 more solutions.
Similarly with x = 3, we will have 5 more solutions.
Similarly with x = 4, we will have 4 more solutions.
Thus,
Total number of solutions = 4 + 5 + 6 + 7 + 8 + 9 + 10 + 10
= 59 integer solutions
Read more about Number of Integral Solutions at; https://brainly.com/question/251701
#SPJ1
