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Find the cube root of 1+¡^5​

Sagot :

bunnuika
  4. ¡^5= ¡
  5. so we have cuberoot of 1+¡
  6. x=1 y=1
  7. to find d modulus we have
  8. r=squaroot of 1²+ 1²= 2
  9. r= squaroot of 2
  10. we find the argard diagram by using
  11. tan(tha)=y/x
  12. tan(tha)=1/1
  13. tha=tan-¹ 1
  14. tha=45
  15. using the formula of root of complex number we have
  16. z=r^1/n (cos(tha+2k(180))/n +¡sin(tha+2k(180)/n) when k elemen z+ and n=3
  17. when k=0
  18. we have
  19. z=(squaroot of 2)^1/3 *1/2squaroot of 2
  20. like wise when k=1 and k=2
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