Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

An ultracentrifuge is spinning at a speed of 80,000 rpm. The rotor that spins with
the sample can be roughly approximated as a uniform cylinder of 10 cm radius
and 8 kg mass, spinning about its symmetry axis). In order to stop the rotor in
under 30 s from when the motor is turned off, find the minimum braking torque
that must be applied.
O-19.2 Nm
-17.2 Nm
O -15.2 Nm
O-11.2 Nm
O None of the above

An Ultracentrifuge Is Spinning At A Speed Of 80000 Rpm The Rotor That Spins With The Sample Can Be Roughly Approximated As A Uniform Cylinder Of 10 Cm Radius An class=

Sagot :

onyebuchinnaji

D. The minimum braking torque that must be applied is -11.2 Nm.

Moment of inertia of the uniform cylinder

The moment of inertia of the uniform cylinder is calculated as follows;

I = ¹/₂MR²

where;

  • M is mass of the cylinder
  • R is radius of the cylinder

I = (0.5)(8)(0.1²)

I = 0.04 kgm²

Minimum braking torque

τ = -Iα

where;

  • α is angular acceleration

α = ω/t

α = (80,000 x 2π/rev x 1 min/60s) / (30 s)

α =  (80,000 x 2π)/(60 x 30)

α = 279.25 rad/s²

τ = - ( 0.04 kgm²) x (279.25)

τ =  -11.2 Nm

Thus, the minimum braking torque that must be applied is -11.2 Nm.

Learn more about minimum braking torque here: https://brainly.com/question/6845979

#SPJ1

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.