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tan 45- cos ~ 60° = x. Sin 45. ta​

Sagot :

The trigonometric values we require :

[tex]\begin{tabular}{c | l}trigonometric value & numerical value \\\cline{1-2}tan 45^{o}& 1 \\cos 60^{o} & 0.5 \\sin 45^{o} & 1 \div \sqrt{2}\end{tabular}[/tex]

Now, let's solve for x.

tan 45° - cos 60° = x (sin 45°)

[tex]\mathrm {1 - \frac{1}{2} = x (\frac{1}{\sqrt{2}})}[/tex]

[tex]\mathrm {\frac{1}{2} = \frac{x}{\sqrt{2}}}[/tex]

[tex]\mathrm {x = \frac{\sqrt{2}}{2}}[/tex]

[tex]\mathrm {x = \frac{1}{\sqrt{2}}}[/tex]

The value of x is 1/√2.

I hope it helped you solve the problem

Good luck on your studies!