Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Need help asap. Picture below to see what I need help with

Need Help Asap Picture Below To See What I Need Help With class=

Sagot :

When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.

The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.

The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.

We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.

Parents: BB x Bb

Gametes: B, B, and B, b

Offspring: BB, BB, Bb, Bb

The genotypic ratio = 1:1

The phenotypic ratio = 1:0

Genotype probabilities:

P(BB) = 2/4 = 0.5 or 50%

P(Bb) = 2/4 = 0.5 or 50%

Learn more about genotype here:

https://brainly.com/question/18101683

#SPJ1

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.