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Find the inverse of the given function.

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anuksha0456

The inverse of the function, f(x) = (-1/2)√(x + 3), x ≥ -3 is f⁻¹(x) = 4x² - 3, for x ≤ - 1/2.

In the question, we are asked to find the inverse of the function, f(x) = (-1/2)√(x + 3), x ≥ -3.

The domain for the given function is x ≥ -3.

Thus, its range is x ≤ - 1/2.

To find the inverse, we equate f(x) = y, to get:

(-1/2)√(x + 3) = y,

or, √(x + 3) = -2y.

Squaring both sides, we get:

x + 3 = (-2y)²,

or, x + 3 = 4y²,

or, x = 4y² - 3.

Thus, the inverse of the function f(x) = (-1/2)√(x + 3), is, f⁻¹(x) = 4x² - 3.

The inverse will have the domain equal to the range of the original function, that is, x ≤ - 1/2.

Thus, the inverse of the function, f(x) = (-1/2)√(x + 3), x ≥ -3 is f⁻¹(x) = 4x² - 3, for x ≤ - 1/2.

Learn more about the inverse of a function at

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The provided question is incomplete. The complete question is:

"Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Find the inverse of the given function.

f(x) = (-1/2)√(x + 3), x ≥ -3

f⁻¹(x) =   x² -   , for x ≤    ."

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