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What is the molality of a solution prepared by dissolving 3. 41 g of c6h12o6 in 85 ml of water:__________

Sagot :

When 3. 41 g of C6H12O6 is dissolved in 85 ml of water the molality is 2.2m.

What is molality?

Molality is the amount of a substance dissolved in a certain mass of solvent.

Molality = moles of solute/ mass of solvent (kg)

Given,

Mass of solute = 3.14g

Molar mass of solute = 180 g

Mole of solute= given mass/molar mass

= 3.14/180

= 0.0189 mol.

Volume of solvent = 85 ml

Density of water = 1 g/cm3

Density = mass/ volume

mass = density × volume

= 1× 85

= 85g

Molality = (0.0189/ 85) × 1000

= 2.2m

Thus we find that the molality of given solution is 2.2m.

learn more about molality:

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