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Consider annaca 2412 airfoil with a 2m chord in an airstream with a velocityof 50m/s at standard sealevel conditions([infinity]=1. 233⁄). ifthe lift per unit span is 1353n/m,what is the angle of attack?

Sagot :

tanisharawat014

The angle of attack of airfoil with a 2m chord in an airstream with a velocity of 50m/s, and the lift per unit span is 1353n/m will be 4 degrees.

To find the answer, we have to know more about the dynamic pressure.

How to find the angle of attack of the airstream?

  • Given that

                        [tex]l=2m\\v=50m/s\\L=1353N/m\\d_{infinity}=1.233Kg/m^3[/tex]

  • We have the expression for dynamic pressure as,

                  [tex]P_d=\frac{1}{2} dv^2=\frac{1}{2}*1.233*50^2=1541.25 Pascals.[/tex]

  • We have the expression for lift coefficient in terms of lift per unit span, dynamic pressure and the chord length l as,

                          [tex]k=\frac{L}{P*l} =\frac{1353}{1541.25*2}=0.438[/tex]

  • We have to find the angle of attack, and which can be defined in terms of k as,

                                  [tex]\alpha =sin^{-1}(\frac{k}{2\pi } )\\\alpha =sin^{-1}(\frac{0.438}{2\pi } )\\\alpha =4.007 degrees.[/tex]

Thus, we can conclude that, the angle of attack of airfoil with a 2m chord in an airstream with a velocity of 50m/s, and the lift per unit span is 1353n/m will be 4 degrees.

Learn more about dynamic pressure here:

https://brainly.com/question/19491032

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