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Sagot :
The voltage drop across an inductor in a circuit with a dc voltage source at time>> 5*time-constant is more than as compared to first case because the voltage across the inductor is proportional to the rate of change of current which is a maximum at the start when the current and the voltage across the resistor are zero.
As time progresses the current increases at a slower rate as does the voltage across the resistor but the voltage across the inductor decreases.
The voltage drop is proportional to the current, which is the rate-change of the charge. Inductors: V = L (DI/Dt). The voltage drop across the inductor is proportional to the rate-change of the current.
How do you calculate voltage drop in an inductor?
The formula which calculates the inductor voltage is
V= Ldi/dt,
where,
V is the voltage across the inductor,
L is the inductance of the inductor,
di/dt is the derivative of the current flowing across the inductor.
Thus from the above conclusion we can say that The voltage drop across an inductor in a circuit with a dc voltage source at time>> 5*time-constant is more than as compared to first case because the voltage across the inductor is proportional to the rate of change of current which is a maximum at the start when the current and the voltage across the resistor are zero.
Learn more about Voltage drop from here: https://brainly.com/question/1176850
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