Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.
Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.
In other words osmolarity is the multiple if molarity
Osmolarity = i× molarity
Here i represents the van't Hoff factor,
[tex]Na_{3}PO_{4}[/tex] ⇒ [tex]3Na^{+} + PO_{4} ^{-}[/tex]
3 Moles of [tex]Na_{} ^{+}[/tex] + 1 mole [tex]PO_{4} ^{-}[/tex] = 4
The number of moles of particles of solute produced in solution are actually called osmoles.
As a result, the van't Hoff factor will be equal to
i=4 Moles ions produced (osmoles) 1mole [tex]Na_{3} PO_{4}[/tex] .dissolved =4
Since we know that,
[tex]Na_{3} PO_{4}[/tex] = [tex]2.0 * 10^{-3} M[/tex]
Osmolarity =
[tex]4*2.0*10^{-3} M[/tex] = [tex]8.0 * 10^{-3} osmol L -10s[/tex]
Thus, the Osmolarity of given solution is 0.008 osmol/L.
learn more about Osmolarity:
https://brainly.com/question/13597129
#SPJ4
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
