At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The binding energy of the electron is 1.237 ×10^(-16) kj/ mol.
The given parameter
wavelength of photon,
λ = 0.999nm
= 0.999x10⁻⁹ m
K.E of emitted photon,
K.E = 940 ev
The binding energy of electron is calculated as follows:
From Einstein's mass defect equation=
ΔE = Δmc²
Also, from Einstein's photo electric equation=
E = Ф + K.E
Where;
Ф is binding energy of electron on metal surface.
The energy of on mole of electron, the emitted is calculated as:
[tex]E = hf =h \frac{c}{λ} = (6.626×10^{-34} ) × \frac{{3×10^{8} }}{0.999×10^{-9} } \\\\E= 1.989×10^{-16}[/tex]
The K.E of emitted electron in Joules is
[tex]K.E = 940 × \frac{1}{2} ×1.602 ×\ 10^{-19} J\\\\ = 0.752 × 10^{-16} J[/tex]
The binding energy is electron is calculated as:
[tex]Ф = E - K.E\\= (1.989 - 0.752) ×10^{-16}\\ =1.237 × 10^{-16} J[/tex]
Question: An X-ray photon of wavelength 0.999nm strikes a surface. The emitted electron has a kinetic energy of 940 eV. What isthe binding energy of the electron in kJ/mol? (KE=1/2mv2; 1 electron volt (eV) = 1.602 x10-19J)
Learn more about binding energy: https://brainly.com/question/15718710
#SPJ4
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
