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How many grams of mgo are produced by the reaction of 25. 0 g of mg with 25. 0 g of o2?

Sagot :

When 25.0 g of Mg react with 25.0 g of O₂ it produce 41.9g of MgO.

Chemical reaction:

2Mg + O₂ → 2 MgO

Given,

Mass of Mg = 24g

Mass of O₂ = 25 g

Molar mass of O₂ = 16×2

= 32 g

Molar mass of Mg = 24.3

Moles of Mg  =25/24.3

=1.04mole

Moles of O₂  =25/32

=0.78mole

From above reaction we can say that 2moles of mg react with 1moles of O₂ to give 2moles of MgO.

So, 1 mole of Mg react with 0.5 mole of O₂ to produce 1mole of MgO.

So, 1.04 react with= 0.5× 1.04

= 0.520 g oxygen to give 1.04 moles of MgO.

From above we can say that Mg is limiting reagent.

Moles of MgO =1.04

Molar mass of MgO =40.3

Mole =given mass/ molar mass

1.04  =mass/ 40.3

Mass = 1.04×40.3

41.9 g

Thus, from above we concluded that 25.0 g of Mg react with 25.0 g of O₂  it produce 41.9g of MgO.

Learn more about limiting reagent: https://brainly.com/question/26905271

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