At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

How many grams of mgo are produced by the reaction of 25. 0 g of mg with 25. 0 g of o2?

Sagot :

When 25.0 g of Mg react with 25.0 g of O₂ it produce 41.9g of MgO.

Chemical reaction:

2Mg + O₂ → 2 MgO

Given,

Mass of Mg = 24g

Mass of O₂ = 25 g

Molar mass of O₂ = 16×2

= 32 g

Molar mass of Mg = 24.3

Moles of Mg  =25/24.3

=1.04mole

Moles of O₂  =25/32

=0.78mole

From above reaction we can say that 2moles of mg react with 1moles of O₂ to give 2moles of MgO.

So, 1 mole of Mg react with 0.5 mole of O₂ to produce 1mole of MgO.

So, 1.04 react with= 0.5× 1.04

= 0.520 g oxygen to give 1.04 moles of MgO.

From above we can say that Mg is limiting reagent.

Moles of MgO =1.04

Molar mass of MgO =40.3

Mole =given mass/ molar mass

1.04  =mass/ 40.3

Mass = 1.04×40.3

41.9 g

Thus, from above we concluded that 25.0 g of Mg react with 25.0 g of O₂  it produce 41.9g of MgO.

Learn more about limiting reagent: https://brainly.com/question/26905271

#SPJ4

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.