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He fuel used in many disposable lighters is liquid butane, c4h10c4h10. butane has a molecular weight of 58. 1 grams in one mole. how many carbon atoms are in 2. 00 gg of butane?

Sagot :

Carbon atoms present in 2. 00 g of butane is 8.28 × 10^22.

Molecular weight of C4H10 is = 58.1 grams

Moles of butane = given mass/ molar mass

= 2/58.1

= 0.0344 mol

Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:

0.0344 x 6.023 x 10^{23} molecules of butane = 2.07 × 10^22 molecules

of butane

Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:

so, no. of carbon atoms = 4 x 2.07x 10^22 = 8.28x 10^22 atoms.

Thus the no. of carbon atom is 8.28×10^22.

learn more about butane or moles:

https://brainly.com/question/899549

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