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How many fe(ii) ions are there in 20. 0 g of feso4 (molar mass=151. 9 g/mol) ? avogadro number=6. 0225x 1023

Sagot :

20 g of [tex]FeSO_4[/tex] contains [tex]7.94 \times 10^{22}[/tex] ions of [tex]Fe^2^+[/tex]

What is Mole?

A mole is a unit to measure an amount of any substance which contains as many elementary particles as there in 12 g of Carbon 12.

A mole contains  [tex]6.02214 \times 10^{23}[/tex] particles and this fixed number is called Avogadro’s number.

No. of moles is given by,

[tex]n =\frac{m}{M}[/tex]

where m = Given mass in grams

M = Molar mass

Here,

[tex]FeSO_4 \rightarrow Fe^2^+ + SO_4^2^-[/tex]

No. of moles of  [tex]FeSO_4[/tex]  = [tex]\frac{20g}{151.9gmol^-^1}[/tex] = 0.132 moles

No. of molecules of  [tex]FeSO_4[/tex] = 0.132 x 6.022 x [tex]10^2^3[/tex] = 7.94 x [tex]10^2^2[/tex]

No. of molecules of  [tex]FeSO_4[/tex] = no. of ions of [tex]Fe^2^+[/tex] = no of ions of [tex]SO_4^2^-[/tex]

Thus, no. of ions  [tex]Fe^2^+[/tex] in 20 g of  [tex]FeSO_4[/tex]  is 7.94 x [tex]10^2^2[/tex]

 

Learn more about the mole concept:

https://brainly.com/question/20668126

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