Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A 600-kg car makes a 90° turn. its speed before the turn is 21. 0 m/s and after the turn it is 24. 0 m/s. what is the magnitude of the change in the car's momentum during the turn?

Sagot :

The magnitude of the change in the car's momentum during the turn is

[tex] = 1.9 \times 10 {}^{3} kgm/s[/tex]

What is momentum?

Momentum can be defined as "mass in motion." All objects have mass,so if an object is moving, then it has momentum - it has its mass in motion.

Given:

V1=21m/s

V2=24m/s

m=600kg

To Find:

momentum

Now using Pythagoras theorem

[tex]f = ((600)(21)) {}^{2} + ((600)(24)) {}^{2} [/tex]

[tex]f = \sqrt{1.59 \times 10 {}^{8} + 2.07 \times 10 {}^{8} } [/tex]

[tex] = 1.9 \times 10 {}^{3} kgm/s[/tex]

learn more about momentum from here: https://brainly.com/question/28165726

#SPJ4

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.