Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
A chemist reacted 0. 2 moles sodium benzoate with 0. 25 moles of hydrochloric acid. if she generated 22 g benzoic acid, the percent yield is 90%.
Reactant + HCl ------ Product
0.2 mol 0.25 22g
mol
Number of moles of reactant = 0.2mol
Molar mass of product = 122.12g
Number of moles of product = given mass/ molar mass
= 22g/ 122.12 g
= 0.180mol
Percent yield = (number of moles of product/ number of moles of reactant) × 100
= (0.180/0.2) × 100
= 90%
Thus we concluded that the percent yield of the given solution is 90%.
learn more about percent yield:
https://brainly.com/question/17042787
#SPJ4
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
